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{"version":3,"file":"SimplexNoise.cjs","sources":["../../src/math/SimplexNoise.ts"],"sourcesContent":["// Ported from Stefan Gustavson's java implementation\n// http://staffwww.itn.liu.se/~stegu/simplexnoise/simplexnoise.pdf\n// Read Stefan's excellent paper for details on how this code works.\n//\n// Sean McCullough banksean@gmail.com\n//\n\nexport interface NumberGenerator {\n random: () => number\n}\n\n// Added 4D noise\nexport class SimplexNoise {\n private grad3 = [\n [1, 1, 0],\n [-1, 1, 0],\n [1, -1, 0],\n [-1, -1, 0],\n [1, 0, 1],\n [-1, 0, 1],\n [1, 0, -1],\n [-1, 0, -1],\n [0, 1, 1],\n [0, -1, 1],\n [0, 1, -1],\n [0, -1, -1],\n ]\n\n private grad4 = [\n [0, 1, 1, 1],\n [0, 1, 1, -1],\n [0, 1, -1, 1],\n [0, 1, -1, -1],\n [0, -1, 1, 1],\n [0, -1, 1, -1],\n [0, -1, -1, 1],\n [0, -1, -1, -1],\n [1, 0, 1, 1],\n [1, 0, 1, -1],\n [1, 0, -1, 1],\n [1, 0, -1, -1],\n [-1, 0, 1, 1],\n [-1, 0, 1, -1],\n [-1, 0, -1, 1],\n [-1, 0, -1, -1],\n [1, 1, 0, 1],\n [1, 1, 0, -1],\n [1, -1, 0, 1],\n [1, -1, 0, -1],\n [-1, 1, 0, 1],\n [-1, 1, 0, -1],\n [-1, -1, 0, 1],\n [-1, -1, 0, -1],\n [1, 1, 1, 0],\n [1, 1, -1, 0],\n [1, -1, 1, 0],\n [1, -1, -1, 0],\n [-1, 1, 1, 0],\n [-1, 1, -1, 0],\n [-1, -1, 1, 0],\n [-1, -1, -1, 0],\n ]\n\n private p: number[] = []\n\n // To remove the need for index wrapping, double the permutation table length\n private perm: number[] = []\n\n // A lookup table to traverse the simplex around a given point in 4D.\n // Details can be found where this table is used, in the 4D noise method.\n private simplex = [\n [0, 1, 2, 3],\n [0, 1, 3, 2],\n [0, 0, 0, 0],\n [0, 2, 3, 1],\n [0, 0, 0, 0],\n [0, 0, 0, 0],\n [0, 0, 0, 0],\n [1, 2, 3, 0],\n [0, 2, 1, 3],\n [0, 0, 0, 0],\n [0, 3, 1, 2],\n [0, 3, 2, 1],\n [0, 0, 0, 0],\n [0, 0, 0, 0],\n [0, 0, 0, 0],\n [1, 3, 2, 0],\n [0, 0, 0, 0],\n [0, 0, 0, 0],\n [0, 0, 0, 0],\n [0, 0, 0, 0],\n [0, 0, 0, 0],\n [0, 0, 0, 0],\n [0, 0, 0, 0],\n [0, 0, 0, 0],\n [1, 2, 0, 3],\n [0, 0, 0, 0],\n [1, 3, 0, 2],\n [0, 0, 0, 0],\n [0, 0, 0, 0],\n [0, 0, 0, 0],\n [2, 3, 0, 1],\n [2, 3, 1, 0],\n [1, 0, 2, 3],\n [1, 0, 3, 2],\n [0, 0, 0, 0],\n [0, 0, 0, 0],\n [0, 0, 0, 0],\n [2, 0, 3, 1],\n [0, 0, 0, 0],\n [2, 1, 3, 0],\n [0, 0, 0, 0],\n [0, 0, 0, 0],\n [0, 0, 0, 0],\n [0, 0, 0, 0],\n [0, 0, 0, 0],\n [0, 0, 0, 0],\n [0, 0, 0, 0],\n [0, 0, 0, 0],\n [2, 0, 1, 3],\n [0, 0, 0, 0],\n [0, 0, 0, 0],\n [0, 0, 0, 0],\n [3, 0, 1, 2],\n [3, 0, 2, 1],\n [0, 0, 0, 0],\n [3, 1, 2, 0],\n [2, 1, 0, 3],\n [0, 0, 0, 0],\n [0, 0, 0, 0],\n [0, 0, 0, 0],\n [3, 1, 0, 2],\n [0, 0, 0, 0],\n [3, 2, 0, 1],\n [3, 2, 1, 0],\n ]\n\n /**\n * You can pass in a random number generator object if you like.\n * It is assumed to have a random() method.\n */\n constructor(r: NumberGenerator = Math) {\n for (let i = 0; i < 256; i++) {\n this.p[i] = Math.floor(r.random() * 256)\n }\n\n for (let i = 0; i < 512; i++) {\n this.perm[i] = this.p[i & 255]\n }\n }\n\n public dot = (g: number[], x: number, y: number): number => {\n return g[0] * x + g[1] * y\n }\n\n public dot3 = (g: number[], x: number, y: number, z: number): number => {\n return g[0] * x + g[1] * y + g[2] * z\n }\n\n public dot4 = (g: number[], x: number, y: number, z: number, w: number): number => {\n return g[0] * x + g[1] * y + g[2] * z + g[3] * w\n }\n\n public noise = (xin: number, yin: number): number => {\n let n0\n let n1\n let n2 // Noise contributions from the three corners\n // Skew the input space to determine which simplex cell we're in\n const F2 = 0.5 * (Math.sqrt(3.0) - 1.0)\n const s = (xin + yin) * F2 // Hairy factor for 2D\n const i = Math.floor(xin + s)\n const j = Math.floor(yin + s)\n const G2 = (3.0 - Math.sqrt(3.0)) / 6.0\n const t = (i + j) * G2\n const X0 = i - t // Unskew the cell origin back to (x,y) space\n const Y0 = j - t\n const x0 = xin - X0 // The x,y distances from the cell origin\n const y0 = yin - Y0\n // For the 2D case, the simplex shape is an equilateral triangle.\n // Determine which simplex we are in.\n // upper triangle, YX order: (0,0)->(0,1)->(1,1)\n let i1 = 0\n // Offsets for second (middle) corner of simplex in (i,j) coords\n let j1 = 1\n if (x0 > y0) {\n i1 = 1\n j1 = 0\n }\n\n // A step of (1,0) in (i,j) means a step of (1-c,-c) in (x,y), and\n // a step of (0,1) in (i,j) means a step of (-c,1-c) in (x,y), where\n // c = (3-sqrt(3))/6\n const x1 = x0 - i1 + G2 // Offsets for middle corner in (x,y) unskewed coords\n const y1 = y0 - j1 + G2\n const x2 = x0 - 1.0 + 2.0 * G2 // Offsets for last corner in (x,y) unskewed coords\n const y2 = y0 - 1.0 + 2.0 * G2\n // Work out the hashed gradient indices of the three simplex corners\n const ii = i & 255\n const jj = j & 255\n const gi0 = this.perm[ii + this.perm[jj]] % 12\n const gi1 = this.perm[ii + i1 + this.perm[jj + j1]] % 12\n const gi2 = this.perm[ii + 1 + this.perm[jj + 1]] % 12\n // Calculate the contribution from the three corners\n let t0 = 0.5 - x0 * x0 - y0 * y0\n if (t0 < 0) {\n n0 = 0.0\n } else {\n t0 *= t0\n n0 = t0 * t0 * this.dot(this.grad3[gi0], x0, y0) // (x,y) of grad3 used for 2D gradient\n }\n\n let t1 = 0.5 - x1 * x1 - y1 * y1\n if (t1 < 0) {\n n1 = 0.0\n } else {\n t1 *= t1\n n1 = t1 * t1 * this.dot(this.grad3[gi1], x1, y1)\n }\n\n let t2 = 0.5 - x2 * x2 - y2 * y2\n if (t2 < 0) {\n n2 = 0.0\n } else {\n t2 *= t2\n n2 = t2 * t2 * this.dot(this.grad3[gi2], x2, y2)\n }\n\n // Add contributions from each corner to get the final noise value.\n // The result is scaled to return values in the interval [-1,1].\n return 70.0 * (n0 + n1 + n2)\n }\n\n // 3D simplex noise\n private noise3d = (xin: number, yin: number, zin: number): number => {\n // Noise contributions from the four corners\n let n0\n let n1\n let n2\n let n3\n // Skew the input space to determine which simplex cell we're in\n const F3 = 1.0 / 3.0\n const s = (xin + yin + zin) * F3 // Very nice and simple skew factor for 3D\n const i = Math.floor(xin + s)\n const j = Math.floor(yin + s)\n const k = Math.floor(zin + s)\n const G3 = 1.0 / 6.0 // Very nice and simple unskew factor, too\n const t = (i + j + k) * G3\n const X0 = i - t // Unskew the cell origin back to (x,y,z) space\n const Y0 = j - t\n const Z0 = k - t\n const x0 = xin - X0 // The x,y,z distances from the cell origin\n const y0 = yin - Y0\n const z0 = zin - Z0\n // For the 3D case, the simplex shape is a slightly irregular tetrahedron.\n // Determine which simplex we are in.\n let i1\n let j1\n let k1 // Offsets for second corner of simplex in (i,j,k) coords\n let i2\n let j2\n let k2 // Offsets for third corner of simplex in (i,j,k) coords\n if (x0 >= y0) {\n if (y0 >= z0) {\n i1 = 1\n j1 = 0\n k1 = 0\n i2 = 1\n j2 = 1\n k2 = 0\n\n // X Y Z order\n } else if (x0 >= z0) {\n i1 = 1\n j1 = 0\n k1 = 0\n i2 = 1\n j2 = 0\n k2 = 1\n\n // X Z Y order\n } else {\n i1 = 0\n j1 = 0\n k1 = 1\n i2 = 1\n j2 = 0\n k2 = 1\n } // Z X Y order\n } else {\n // x0<y0\n\n if (y0 < z0) {\n i1 = 0\n j1 = 0\n k1 = 1\n i2 = 0\n j2 = 1\n k2 = 1\n\n // Z Y X order\n } else if (x0 < z0) {\n i1 = 0\n j1 = 1\n k1 = 0\n i2 = 0\n j2 = 1\n k2 = 1\n\n // Y Z X order\n } else {\n i1 = 0\n j1 = 1\n k1 = 0\n i2 = 1\n j2 = 1\n k2 = 0\n } // Y X Z order\n }\n\n // A step of (1,0,0) in (i,j,k) means a step of (1-c,-c,-c) in (x,y,z),\n // a step of (0,1,0) in (i,j,k) means a step of (-c,1-c,-c) in (x,y,z), and\n // a step of (0,0,1) in (i,j,k) means a step of (-c,-c,1-c) in (x,y,z), where\n // c = 1/6.\n const x1 = x0 - i1 + G3 // Offsets for second corner in (x,y,z) coords\n const y1 = y0 - j1 + G3\n const z1 = z0 - k1 + G3\n const x2 = x0 - i2 + 2.0 * G3 // Offsets for third corner in (x,y,z) coords\n const y2 = y0 - j2 + 2.0 * G3\n const z2 = z0 - k2 + 2.0 * G3\n const x3 = x0 - 1.0 + 3.0 * G3 // Offsets for last corner in (x,y,z) coords\n const y3 = y0 - 1.0 + 3.0 * G3\n const z3 = z0 - 1.0 + 3.0 * G3\n // Work out the hashed gradient indices of the four simplex corners\n const ii = i & 255\n const jj = j & 255\n const kk = k & 255\n const gi0 = this.perm[ii + this.perm[jj + this.perm[kk]]] % 12\n const gi1 = this.perm[ii + i1 + this.perm[jj + j1 + this.perm[kk + k1]]] % 12\n const gi2 = this.perm[ii + i2 + this.perm[jj + j2 + this.perm[kk + k2]]] % 12\n const gi3 = this.perm[ii + 1 + this.perm[jj + 1 + this.perm[kk + 1]]] % 12\n // Calculate the contribution from the four corners\n let t0 = 0.6 - x0 * x0 - y0 * y0 - z0 * z0\n if (t0 < 0) {\n n0 = 0.0\n } else {\n t0 *= t0\n n0 = t0 * t0 * this.dot3(this.grad3[gi0], x0, y0, z0)\n }\n\n let t1 = 0.6 - x1 * x1 - y1 * y1 - z1 * z1\n if (t1 < 0) {\n n1 = 0.0\n } else {\n t1 *= t1\n n1 = t1 * t1 * this.dot3(this.grad3[gi1], x1, y1, z1)\n }\n\n let t2 = 0.6 - x2 * x2 - y2 * y2 - z2 * z2\n if (t2 < 0) {\n n2 = 0.0\n } else {\n t2 *= t2\n n2 = t2 * t2 * this.dot3(this.grad3[gi2], x2, y2, z2)\n }\n\n let t3 = 0.6 - x3 * x3 - y3 * y3 - z3 * z3\n if (t3 < 0) {\n n3 = 0.0\n } else {\n t3 *= t3\n n3 = t3 * t3 * this.dot3(this.grad3[gi3], x3, y3, z3)\n }\n\n // Add contributions from each corner to get the final noise value.\n // The result is scaled to stay just inside [-1,1]\n return 32.0 * (n0 + n1 + n2 + n3)\n }\n\n // 4D simplex noise\n public noise4d = (x: number, y: number, z: number, w: number): number => {\n // For faster and easier lookups\n const grad4 = this.grad4\n const simplex = this.simplex\n const perm = this.perm\n\n // The skewing and unskewing factors are hairy again for the 4D case\n const F4 = (Math.sqrt(5.0) - 1.0) / 4.0\n const G4 = (5.0 - Math.sqrt(5.0)) / 20.0\n let n0\n let n1\n let n2\n let n3\n let n4 // Noise contributions from the five corners\n // Skew the (x,y,z,w) space to determine which cell of 24 simplices we're in\n const s = (x + y + z + w) * F4 // Factor for 4D skewing\n const i = Math.floor(x + s)\n const j = Math.floor(y + s)\n const k = Math.floor(z + s)\n const l = Math.floor(w + s)\n const t = (i + j + k + l) * G4 // Factor for 4D unskewing\n const X0 = i - t // Unskew the cell origin back to (x,y,z,w) space\n const Y0 = j - t\n const Z0 = k - t\n const W0 = l - t\n const x0 = x - X0 // The x,y,z,w distances from the cell origin\n const y0 = y - Y0\n const z0 = z - Z0\n const w0 = w - W0\n\n // For the 4D case, the simplex is a 4D shape I won't even try to describe.\n // To find out which of the 24 possible simplices we're in, we need to\n // determine the magnitude ordering of x0, y0, z0 and w0.\n // The method below is a good way of finding the ordering of x,y,z,w and\n // then find the correct traversal order for the simplex we’re in.\n // First, six pair-wise comparisons are performed between each possible pair\n // of the four coordinates, and the results are used to add up binary bits\n // for an integer index.\n const c1 = x0 > y0 ? 32 : 0\n const c2 = x0 > z0 ? 16 : 0\n const c3 = y0 > z0 ? 8 : 0\n const c4 = x0 > w0 ? 4 : 0\n const c5 = y0 > w0 ? 2 : 0\n const c6 = z0 > w0 ? 1 : 0\n const c = c1 + c2 + c3 + c4 + c5 + c6\n // The integer offsets for the second simplex corner\n let i1\n let j1\n let k1\n let l1\n\n // The integer offsets for the third simplex corner\n let i2\n let j2\n let k2\n let l2\n\n // The integer offsets for the fourth simplex corner\n let i3\n let j3\n let k3\n let l3\n // simplex[c] is a 4-vector with the numbers 0, 1, 2 and 3 in some order.\n // Many values of c will never occur, since e.g. x>y>z>w makes x<z, y<w and x<w\n // impossible. Only the 24 indices which have non-zero entries make any sense.\n // We use a thresholding to set the coordinates in turn from the largest magnitude.\n // The number 3 in the \"simplex\" array is at the position of the largest coordinate.\n i1 = simplex[c][0] >= 3 ? 1 : 0\n j1 = simplex[c][1] >= 3 ? 1 : 0\n k1 = simplex[c][2] >= 3 ? 1 : 0\n l1 = simplex[c][3] >= 3 ? 1 : 0\n // The number 2 in the \"simplex\" array is at the second largest coordinate.\n i2 = simplex[c][0] >= 2 ? 1 : 0\n j2 = simplex[c][1] >= 2 ? 1 : 0\n k2 = simplex[c][2] >= 2 ? 1 : 0\n l2 = simplex[c][3] >= 2 ? 1 : 0\n // The number 1 in the \"simplex\" array is at the second smallest coordinate.\n i3 = simplex[c][0] >= 1 ? 1 : 0\n j3 = simplex[c][1] >= 1 ? 1 : 0\n k3 = simplex[c][2] >= 1 ? 1 : 0\n l3 = simplex[c][3] >= 1 ? 1 : 0\n // The fifth corner has all coordinate offsets = 1, so no need to look that up.\n const x1 = x0 - i1 + G4 // Offsets for second corner in (x,y,z,w) coords\n const y1 = y0 - j1 + G4\n const z1 = z0 - k1 + G4\n const w1 = w0 - l1 + G4\n const x2 = x0 - i2 + 2.0 * G4 // Offsets for third corner in (x,y,z,w) coords\n const y2 = y0 - j2 + 2.0 * G4\n const z2 = z0 - k2 + 2.0 * G4\n const w2 = w0 - l2 + 2.0 * G4\n const x3 = x0 - i3 + 3.0 * G4 // Offsets for fourth corner in (x,y,z,w) coords\n const y3 = y0 - j3 + 3.0 * G4\n const z3 = z0 - k3 + 3.0 * G4\n const w3 = w0 - l3 + 3.0 * G4\n const x4 = x0 - 1.0 + 4.0 * G4 // Offsets for last corner in (x,y,z,w) coords\n const y4 = y0 - 1.0 + 4.0 * G4\n const z4 = z0 - 1.0 + 4.0 * G4\n const w4 = w0 - 1.0 + 4.0 * G4\n // Work out the hashed gradient indices of the five simplex corners\n const ii = i & 255\n const jj = j & 255\n const kk = k & 255\n const ll = l & 255\n const gi0 = perm[ii + perm[jj + perm[kk + perm[ll]]]] % 32\n const gi1 = perm[ii + i1 + perm[jj + j1 + perm[kk + k1 + perm[ll + l1]]]] % 32\n const gi2 = perm[ii + i2 + perm[jj + j2 + perm[kk + k2 + perm[ll + l2]]]] % 32\n const gi3 = perm[ii + i3 + perm[jj + j3 + perm[kk + k3 + perm[ll + l3]]]] % 32\n const gi4 = perm[ii + 1 + perm[jj + 1 + perm[kk + 1 + perm[ll + 1]]]] % 32\n // Calculate the contribution from the five corners\n let t0 = 0.6 - x0 * x0 - y0 * y0 - z0 * z0 - w0 * w0\n if (t0 < 0) {\n n0 = 0.0\n } else {\n t0 *= t0\n n0 = t0 * t0 * this.dot4(grad4[gi0], x0, y0, z0, w0)\n }\n\n let t1 = 0.6 - x1 * x1 - y1 * y1 - z1 * z1 - w1 * w1\n if (t1 < 0) {\n n1 = 0.0\n } else {\n t1 *= t1\n n1 = t1 * t1 * this.dot4(grad4[gi1], x1, y1, z1, w1)\n }\n\n let t2 = 0.6 - x2 * x2 - y2 * y2 - z2 * z2 - w2 * w2\n if (t2 < 0) {\n n2 = 0.0\n } else {\n t2 *= t2\n n2 = t2 * t2 * this.dot4(grad4[gi2], x2, y2, z2, w2)\n }\n\n let t3 = 0.6 - x3 * x3 - y3 * y3 - z3 * z3 - w3 * w3\n if (t3 < 0) {\n n3 = 0.0\n } else {\n t3 *= t3\n n3 = t3 * t3 * this.dot4(grad4[gi3], x3, y3, z3, w3)\n }\n\n let t4 = 0.6 - x4 * x4 - y4 * y4 - z4 * z4 - w4 * w4\n if (t4 < 0) {\n n4 = 0.0\n } else {\n t4 *= t4\n n4 = t4 * t4 * this.dot4(grad4[gi4], x4, y4, z4, w4)\n }\n\n // Sum up and scale the result to cover the range [-1,1]\n return 27.0 * (n0 + n1 + n2 + n3 + n4)\n 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